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0=10t+6.25t^2+10
We move all terms to the left:
0-(10t+6.25t^2+10)=0
We add all the numbers together, and all the variables
-(10t+6.25t^2+10)=0
We get rid of parentheses
-6.25t^2-10t-10=0
a = -6.25; b = -10; c = -10;
Δ = b2-4ac
Δ = -102-4·(-6.25)·(-10)
Δ = -150
Delta is less than zero, so there is no solution for the equation
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